Розкрий дужки й обчисли:
Розв'язок:
1) $0{,}7 + \left(5{,}3 - 4\frac{2}{3}\right) = 0{,}7 + 5{,}3 - 4\frac{2}{3} =$
$= 5\frac{3}{3} - 4\frac{2}{3} = 1\frac{1}{3}$;
2) $-\left(4\frac{5}{12} - 2\frac{5}{6}\right) + 1\frac{5}{12} =$
$= -4\frac{5}{12} + 2\frac{5}{6} + 1\frac{5}{12} = 2\frac{5}{6} - 3 =$
$= -\left(2\frac{6}{6} - 2\frac{5}{6}\right) = -\frac{1}{6}$;
3) $\left(1{,}8 - 4\frac{1}{2}\right) - \left(5\frac{1}{2} + 1{,}8\right) =$
$= 1{,}8 - 4\frac{1}{2} - 5\frac{1}{2} - 1{,}8 = -10$;
4) $3\frac{2}{7} - \left(4\frac{1}{3} - 6\frac{5}{7}\right) = 3\frac{2}{7} - 4\frac{1}{3} + 6\frac{5}{7} =$
$= 10 - 4\frac{1}{3} = 9\frac{3}{3} - 4\frac{1}{3} = 5\frac{2}{3}$;
5) $-\left(5\frac{5}{6} - 2\frac{2}{3}\right) + 3\frac{1}{9} =$
$= -5\frac{5}{6} + 2\frac{2}{3} + 3\frac{1}{9} =$
$= 5\frac{6+1}{9} - 5\frac{5}{6} = \frac{7}{9} - \frac{5}{6} =$
$= \frac{14}{18} - \frac{15}{18} = -\frac{1}{18}$;
6) $-\left(1{,}9 - 2\frac{1}{3}\right) + \left(3\frac{2}{3} - 1{,}1\right) =$
$= -1{,}9 + 2\frac{1}{3} + 3\frac{2}{3} - 1{,}1 = 6 - 3 = 3$.