Завдання:
Обчисли, використовуючи розподільну властивість множення:
1) –99 ⋅ 17;
2) –12 ⋅ 101;
3) –999 ⋅ (–13);
4) –1001 ⋅ 29.
Розв'язок:
1) -99 ⋅ 17 = (1 – 100) ⋅ 17 = 1 ⋅ 17 – 100 ⋅ 17 = 17 – 1700 = -1683
2) -12 ⋅ 101 = -12 ⋅ (100 + 1) = -12 ⋅ 100 – 12 ⋅ 1 = -1200 – 12 = -1212
3) -999 ⋅ (-13) = (1 – 1000) ⋅ (-13) = 1 ⋅ (-13) – 1000 ⋅ (-13) = -13 + 13000 = 12987
4) -1001 ⋅ 29 = -(1000 + 1) ⋅ 29 = -(29 ⋅ 1000 + 29 ⋅ 1) = -(29000 + 29) = -29029