Виконай дії:
Розв'язок:
1) $3\frac{1}{3} \cdot \left(-2\frac{3}{4} : 5\frac{1}{2}\right) =$
$= \frac{10}{3} \cdot \left(-\frac{11}{4} : \frac{11}{2}\right) =$
$= \frac{10}{3} \cdot \left(-\frac{11}{4} \cdot \frac{2}{11}\right) =$
$= \frac{10}{3} \cdot \left(-\frac{1}{2}\right) = -\frac{5}{3} = -1\frac{2}{3}$;
2) $2\frac{2}{5} : \left(1\frac{11}{15} - 3\frac{2}{5}\right) \cdot \left(-\frac{5}{6}\right) =$
$= \frac{12}{5} : \left(\frac{26}{15} - \frac{17}{5}\right) \cdot \left(-\frac{5}{6}\right) =$
$= \frac{12}{5} : \left(-\frac{5}{3}\right) \cdot \left(-\frac{5}{6}\right) =$
$= 2 \cdot \frac{3}{5} = \frac{6}{5} = 1\frac{1}{5}$;
3) $\left(63{,}45 : (-4{,}7) + 9{,}3\right) : \left(-4\frac{1}{5}\right) =$
$= \left(\frac{1269}{20} : \left(-\frac{47}{10}\right) + \frac{93}{10}\right) : \left(-\frac{21}{5}\right) =$
$= \left(-\frac{1269}{20} \cdot \frac{10}{47} + \frac{93}{10}\right) : \left(-\frac{21}{5}\right) =$
$= \left(-\frac{27}{2} + \frac{93}{10}\right) : \left(-\frac{21}{5}\right) =$
$= -\frac{21}{5} : \left(-\frac{21}{5}\right) = 1$;
4) $\left(-50\frac{2}{5} : (-5{,}6) + 6{,}4\right) : \left(-1\frac{2}{5}\right) =$
$= \left(-\frac{252}{5} : \left(-\frac{28}{5}\right) + 6{,}4\right) : \left(-\frac{7}{5}\right) =$
$= \left(\frac{252}{5} \cdot \frac{5}{28} + 6{,}4\right) : \left(-\frac{7}{5}\right) =$
$= (9 + 6{,}4) : \left(-\frac{7}{5}\right) = 15{,}4 : \left(-\frac{7}{5}\right) =$
$= \frac{77}{5} : \left(-\frac{7}{5}\right) = -\frac{77}{5} \cdot \frac{5}{7} = -11$.